NECO General Mathematics Questions and Answer Solution - May/June 2017 Expo Runz

/ means division or divide

Log means logarithm

* means multiplication

^ means Raise to power

Tita means θ

Pie means π

Base means subscript

Sqr root means √

bar means a dash on top a number of letter

---(1) means equation 1

Proportional means ∝

**VERIFIED**

**Verified-Maths-Obj**

**1CDAAEDEECE**

**11EEBABAABCC**

**21BBCEDABECD**

**31BCCCDDCADE**

**41BDCBDCCECD**

**51BCDCBEDCDB**

**1)**

**tabulate**

**Number- **

**5932**

***6141**

**num**

**3679**

***3113**

**den**

**Log **

**3.7732**

**3.7882**

**7.5612**

**3.5657**

**3.4931**

**7.0588**

**anti log**

**7.5612**

**7.0588/0.5024/3=0.1675**

**anti log**

**=1471*10**

**2)**

**a = 3, b = 20, C = -7**

**Sum is**

**(α/1 + 1/β + β/1 + 1/ α) Note α means Alpha**

**α^2 β + β^2 + α + β / α β**

**= -7/3 (-20/3) + (-20/3) = 140/9 - 20/3 / -7/3 (Note / means**

**Divided)**

**= 80/9 x -3/7 = -80/21**

**Product:**

**-7/3 + 2 + 1/-7/3 = -7/3 + 2/1 - 3/7**

**= -49+42-9/21**

**= -16/21**

**x^2 - (sum)x + product= 0**

**x^2 - 80/21x + (-16/21) = 0**

**Final Answer : 21x^2 - 80x - 16 = 0**

**3a)**

**P=100I/RT=100*30,000/4*3**

**P=N250,000**

**3b)**

**#7000 T0 FRANCS**

**8FRANS= #1**

**?FRANCS =7000**

**CROSS MULTIPLY**

**=#56,000 FRANCS**

**SPENDING 49,400 FRANCS**

**56,000-49,400 = 6600**

**CONVERTING 6,600 FRANCS TO # AT 10 FRANCS TO 1#**

**10 FRANCS—– 1#**

**6600 FRANCS—?#**

**=6,600/10 X1**

**4i)**

**difference in latitude=36degree + 36 degree =72degree**

**distance travelled=@/360*2pir**

**=72/360*2*22/77*64**

**=20275200/2520**

**=8045.71**

**=8050km(35.f)**

**4ii)**

**given that speed =800km/hr**

**distance travelled =804571km**

**time=distance travelled/speed**

**=8045.71/800**

**=10.057**

**=10hrs(to the nearest hour)**

**5)**

**tabulate**

**Mark- 21-25,26-30,31-35,36-40,41-45,46-50**

**F- 6,8,12,4,6,4=40**

**X- 23,28,33,38,43,48**

**FX- 138,224,396,152,258,192=1360**

**Class Boundaries- 20.5-20.5, 25.5-30.5,35.5-40.50,40.5-45.5**

**5i)**

**MEAN**

**(X)=EFX/EF=1360/40=34**

**MODE**

**L1+[Fm-Fa/2fm-fa-fb]c**

**=30.5+[12-8/2(12)-8-4]5**

**=30.5+[4/12]5**

**=30.5+1.67**

**=32.17**

**SECTION B**

**ANSWER 5 QUESTIONS**

**6i)**

**7+8+x*x=47**

**15+2x=47**

**2x=47-15**

**2x/2 =32/2**

**x=16**

**6ii)**

**Tram only**

**7+8+3+y =30**

**18+y =30**

**y=30-18=12**

**Tram only =12**

**6iii)**

**at least two **

**7+16+3+8**

**=34//**

**6iv)**

**16+7+12+16+8+3+9=95**

**62+9=95**

**9=95-62**

**9=33// or car only =33**

**7a)**

**a+2d=11 ----eq (1)**

**-(a+8d)=29 ----eq (2)**

**-6d/-6d = -18/-6**

**d=3**

**sub for d=3 in ----eq (1)**

**a+2(3)=11**

**a+6=11**

**a=11-6=5**

**7b)**

**L = ar^n-1**

**729/3 = 3/3 x 3^n-1**

**243 = 3^n-1**

**3^5 = 3^-1**

**5 = n-1**

**N = 5+1 **

**= 6**

**Sn = a(r^-1)/r-1 = 3(3^6 - 1)/3-1**

**Sn = 3( 729 -1)/2**

**S6 = 3 x 728/2**

**S6 = 1092**

**7c)**

**3x^3/3 + x | 2,1**

**(2^3 + 2) - (1^3+1)**

**(8+2) - (1+1)**

**= 8**

**8ai)**

**y=(4x+9)^3**

**let u =4x+9, y=U^3**

**du/dx=4, dy/du=3U^2**

**dy/dx=dy/du * du/dx = 4*3u^2=12u^2**

**recall= U=4x+9**

**dy/dx=12(4x+9)^2**

**8aii)**

**y=(3x-2)^3 (x^2 + 4)^2**

**u=(3x-2)^3 V=(x^2+4)^2**

**du/dx=3.3(3x-2)^3-1 , dv/dx=2x.2(x^2+4)^2-1 **

**=4x(x^2+4)**

**in other words**

**dy/dx=Vdu/dx + udv/dx**

**=(x^2+4)^2 9 (3x-2)^2+(3x-2)^3 4x(3x-2)**

**=(x^2+4) (3x-2)^2 (9x^2+36+12x^2-8x)**

**=(x^2+4) (3x-2)^2 (21x^2-8x+36)**

**8b)**

**y-y1=m(x-x1)**

**y-6=2(x-2)**

**y-6=2x-4**

**y=2x-4+6=2x+2**

**9)**

**TYPING IT OUT**

**10)**

**TYPING IT OUT**

**11a)**

**Tabulate**

**X- |-1| |0| |1| |2| |3| |4| **

**6 |6| |6| |6| |6| |6| |6|**

**+X |-1| |0| |1| |2| |3| |4|**

**-X^2 |-1| |0| |-1| |-4| |-9| |16|**

**Y- |4| |6| |6| |4| |0| |-6|**

**11b)**

**1ci)**

**gradient at x/x**

**dy/dx =B-A/B-C**

**=7-4/2-1=3/1=3**

**11cii)**

**roots of equation from the graph **

**x=-2.2 and x=3**

**11ciii)**

**minimum value of y**

**=6.4.**

**12a)**

**from economics**

**3x+2y-12=90**

**3x+2y=90+12**

**3x+2y=102 -----(1)**

**sum of angle in a circle=360degree**

**5x+y-9+3x+2y-12+3y**

**+4x+21=360**

**5x+3x+4x+y+2y+3y-9-12+21=360**

**12x+6y=360 -----(2)**

**solving equation 1and2**

**simulteanously**

**13x+2y=102**

**12x+6y=360**

**using elimination method**

**3x+2y=102*4**

**12x+8y=408**

**12x+6y=360**

**2y/2=48/2**

**y=24**

**substitute y=24 into **

**equation (1) for x**

**3x + 2y =102**

**3x+2*24=102**

**3x+48=102**

**3x=102-48**

**3x/3=54/3**

**x=18**

**x+y=18+24**

**x+y=42**

**12b)**

**candidate that registerd for literature**

**=4x+21/360 * 1200**

**=4*18+21/360 * 1200**

**=72+21/360 * 1200**

**93/360*1200 =111600/360**

**=310**

**candidate that registered for government **

**=3y/360 * 1200**

**=3*24/360 * 1200**

**=72/360 * 1200 =86400/360**

**=240**

**310 - 240 = 70**

**the candidate that registered for litereature are 70, more than candidate that registered for government**

**COMPLETED**

=========================

*Expospy.com posts all exam expo answer earlier than others*

============================

**GOODLUCK!!!**

We appreciate you for reading our post, but we think it will be better you like our facebook fanpage and also follow us on twitter below.